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C program to interchange the rows in the matrix
Here, we are going to learn how to interchange the rows in the matrix in C programming language?
Submitted by Nidhi, on July 13, 2021
Problem Solution:
Given a matrix, and we have to interchange the specified rows in the matrix using C program.
Program:
The source code to interchange the rows in the matrix is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully.
// C program to interchange the rows in matrix
#include <stdio.h>
int main()
{
int Matrix[3][3] = {
{ 1, 2, 3 },
{ 4, 5, 6 },
{ 7, 8, 9 }
};
int i, j, n1, n2, temp;
printf("Matrix before row exchange:\n");
for (i = 0; i < 3; ++i) {
for (j = 0; j < 3; ++j)
printf(" %d", Matrix[i][j]);
printf("\n");
}
printf("Enter two row numbers to be exchanged:");
scanf("%d %d", &n1, &n2);
//Exchange rows
for (i = 0; i < 3; ++i) {
temp = Matrix[n1 - 1][i];
Matrix[n1 - 1][i] = Matrix[n2 - 1][i];
Matrix[n2 - 1][i] = temp;
}
printf("Matrix after row exchange:\n");
for (i = 0; i < 3; ++i) {
for (j = 0; j < 3; ++j)
printf(" %d", Matrix[i][j]);
printf("\n");
}
return 0;
}
Output:
RUN 1:
Matrix before row exchange:
1 2 3
4 5 6
7 8 9
Enter two row numbers to be exchanged:1 3
Matrix after row exchange:
7 8 9
4 5 6
1 2 3
RUN 2:
Matrix before row exchange:
1 2 3
4 5 6
7 8 9
Enter two row numbers to be exchanged:1 2
Matrix after row exchange:
4 5 6
1 2 3
7 8 9
RUN 3:
Matrix before row exchange:
1 2 3
4 5 6
7 8 9
Enter two row numbers to be exchanged:2 3
Matrix after row exchange:
1 2 3
7 8 9
4 5 6
Explanation:
In the main() function, we created a 3X3 matrix matrix using the 2D array. Then we read row numbers to be exchanged. After that, we interchanged the rows and printed the updated matrix on the console screen.
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