# C program to calculate the sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms

Here, we are going to implement a c program that will find the sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms.
Submitted by IncludeHelp, on March 04, 2018

## Program to calculate sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms in C

﻿

```#include <stdio.h>
#include <math.h>

int main()
{
int x,n,i;
float sum=0;

printf("Enter total number of terms: ");
scanf("%d",&n);

printf("Enter the value of x: ");
scanf("%d",&x);

for(i=1; i<=n; i++){
sum += 1+(1/pow(x,i));
}

printf("Sum of the series: %f\n",sum);
return 0;
}
```

Output

```Enter total number of terms: 5
Enter the value of x: 2
Sum of the series: 5.968750
```

Solution

```Series is:
1+1/x^1 + 1/x^2+ 1/x^3 ... + 1/x^n

Here,
x=2
n=5

1+1/2^1 + 1+1/2^2 + 1+1/2^3 + 1+1/2^4 + 1+1/2^5
1+1/2 + 1+1/4 + + 1+1/8 + 1+1/16 + 1+1/32
1+0.5 + 1+0.25 + 1+0.125 + 1+0.0625 + 1+0.03125
= 5.968750
```

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