# C program to find the sum of series 1.2/3 + 2.3/4 + 3.4/5 + 4.5/6 + ... + n(n +1)/(n+2)

In this C program, we are going to find the sum of series 1.2/3 + 2.3/4 + 3.4/5 + 4.5/6 + ... + n(n +1)/(n+2), where value of n will be provided by the user.
Submitted by IncludeHelp, on March 18, 2018

Given the value of n and we have to find the sum of series 1.2/3 + 2.3/4 + 3.4/5 + 4.5/6 + ... + n(n +1)/(n+2) Using C program.

## Program to find the sum of series 1.2/3 + 2.3/4 + 3.4/5 + 4.5/6 + ... + n(n +1)/(n+2) in C

```/*
C program to find sum of following series
* 1.2/3 + 2.3/4 + 3.4/5 + 4.5/6 + ... + n(n +1)/(n+2)
*/

#include <stdio.h>
#include <math.h>

// main function
int main()
{
int i,N,x;
float sum;

printf("Enter total number of terms: ");
scanf("%d",&N);

/*set sum by 0*/
sum=0.0f;

/*calculate sum of the series*/
for(i=1;i<=N;i++)
{
sum = sum + ( (float)(N)*(N+1) / (float)(N+2));
}

/*print the sum*/
printf("Sum of the series is: %f\n",sum);

return 0;
}
```

Output

```Run(1)
Enter total number of terms: 3
Sum of the series is: 7.200000

Run(2)
Enter total number of terms: 4
Sum of the series is: 13.333333
```