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C program to find two smallest elements in a one dimensional array
In this article we are going to implement a C program to find two smallest elements in a one dimensional array.
Submitted by Radib Kar, on December 10, 2018
Problem statement: Write a C program to find two smallest elements in a one dimensional array.
Example: Type1: (all the elements are not same & no of element is more than two)
Array size: 4
Elements: 32 54 -6 43
Output: -6 32
Example: Type2: (second minimum doesn’t exist as size of array < 2)
Array size : 1
Elements: 4
Output: 4
Example: Type3: (all elements are same, thus only one smallest element)
Array size : 4
Elements: 13 13 13 13
Output: 13
Algorithm:
- Define two variable min & sec_min
- Initialize min to array[0] & sec_min to INT_MAX
- Scan the entire array
For(int i=0;i<n;i++)
if array[i]<min
then update min to array[i]&sec_min to previousmin value
else if array[i] is lesser than sec_min but greater than min
then update sec_min to array value
do nothing to min
End for loop
- If still sec_min has the value INT_MAX
Only one smallest value exists, print it
Else
Print min & sec_min
C implementation to find two smallest elements in a one dimensional array
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
void findTwoMin(int* a,int n){
int min=a[0]; //initialize min to first array element
int sec_min=INT_MAX,temp=0; //initialize second min to INT_MAX
for(int i=0;i<n;i++){ //scan the entire array
//if a[i]< min then update min to array value
//& second min to previous min value
if(a[i]<min){
sec_min=min;
min=a[i];
}
//else if a[i] is lesser than second min but
//greater than min then update second min to array value
else if (a[i] < sec_min && a[i] > min)
sec_min=a[i];
//do nothing to min
}
//if second min is still at its initialized value
//then no second minimum exists at all
if(sec_min==INT_MAX)
printf("only one smallest element: %d ",min);
else
printf("First smallest element: %d & second smallest element : %d",min,sec_min);
}
int main(){
int n;
printf("enter no of elements\n");
scanf("%d",&n);
//dynamic array created
int *a=(int*) malloc(sizeof(int)*n);
printf("enter the elements........\n");
//taking input
for(int i=0;i<n;i++)
scanf("%d",&a[i]);
//find two smallest no
findTwoMin(a,n);
return 0;
}
Output (Type1 example)
enter no of elements
4
enter the elements........
32 54 -6 43
First smallest element: -6 & second smallest element : 32
Output (Type2 example)
enter no of elements
1
enter the elements........
4
only one smallest element: 4
Output (Type3 example)
enter no of elements
4
enter the elements........
13 13 13 13
only one smallest element: 13
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