# C program to find odd or even number using bitmasking

In this article, we are going to see how to check a number odd or even using bitwise operators?
Submitted by Radib Kar, on December 30, 2018

Problem statement: Write a C program to find odd or even no using bitwise operators.

Solution: We can use bitwise operator here to solve the problem.

Solution

```    Let n be a number
n &1 = 0000000d where d is the LSB of n
So,
If LSB ==1
It's odd number
Else
Even no
```

To understand the concept of "LSB" & bitwise operators please read: Bitwise Operators and their working with Examples in C

Example:

```    Let n be 7 //00000111
n & 1 = 1
00000111(7) & 00000001(1) =00000001 (1)
Thus it's an odd number
Let n be 6 //00000110
N&1=0
00000110(6) & 00000001(1) =00000000 (0)
Thus it's an even number
```

C implementation

```#include <stdio.h>

int main()
{
int n;

printf("enter no: ");

scanf("%d",&n);

//n&1 actually results in 0000000d where d is your LSB
if(n&1==1)
printf("it's odd no");//for odd no LSB 1
else
printf("it's even no");//for even no LSB 0

return 0;
}
```

Output

```First run:
enter no: 7
it's odd no

Second run:
enter no: 6
it's even no
```

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