# Fibonacci series program | 8085 Microprocessor

Here, we are going to write a Fibonacci series program using 8085 microprocessor?
Submitted by Ayush Sharma, on November 05, 2018

Problem statement:

Write an assembly language program in 8085 microprocessor to generate Fibonacci series.

Example: Assume Fibonacci series is stored at starting memory location 3050.

```    3050 = 00, 3051 = 01, 3052 = 02, 3053 = 03 and so on.
```

Note: This program generates Fibonacci series in hexadecimal numbers.

Algorithm:

1. Initialize register H with 30 and register L with 50, so that indirect memory M points to memory location 3050.
2. Initialize register B with 00, register C with 08 and register D with 01.
3. Move the content of B in M.
4. Increment M by 1 so that M points to next memory location.
5. Move the content of D in M.
6. Move the content of B in accumulator A.
7. Add the content of D in A.
8. Move the content of D in B.
9. Move the content of A in D.
10. Increment M by 1 so that M points to next memory location.
11. Move the content of A in M.
12. Decrements C by 1.
13. Jump to memory location 200D if ZF = 0 otherwise Halt the program.

Program:

2000LXI H, 3050H ← 30, L ← 50
2003MVI C, 08C ← 08
2005MVI B, 00B ← 00
2007MVI D, 01D ← 01
2009MOV M, BM ← B
200AINX HM ← M + 01
200BMOV M, DM ← D
200CMOV A, BA ← B
200DADD DA ← A + D
200EMOV B, DB ← D
2010INX HM ← M + 01
2011MOV M, AM ← A
2012DCR CC ← C – 01
2013JNZ 200DJump if ZF = 0
2016HLTEND

Explanation: Registers A, B, C, D, H, L are used for general purpose.

1. LXI H 3050: assigns 30 to H and 50 to L.
2. MVI B, 00: assigns 00 to B.
3. MVI C, 08: assigns 08 to C.
4. MVI D, 01: assigns 01 to D.
5. MOV M, B: moves the content of B in M.
6. INX H: increment M by 1.
7. MOV M, D: moves the content of D in M.
8. MOV A, B: moves the content of B in A.
9. ADD D: add the content of D and A. Store the result in A.
10. MOV B, D: moves the content of D in B.
11. MOV D, A: moves the content of A in D.
12. INX H: increment M by 1.
13. MOV M, A: moves the content of A in M.
14. DCR C: decrements C by 1.
15. JNZ 200C: jump to memory location 200D if ZF = 0.
16. HLT: stops executing the program and halts any further execution.

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