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C program to find sum of array elements using Dynamic Memory Allocation

Dynamic Memory Allocation Example: In this C program, we will declare memory for array elements (limit will be at run time) using malloc(), read element and print the sum of all elements along with the entered elements.

This program is an example of Dynamic Memory Allocation, here we are declaring memory for N array elements at run time using malloc() - which is used to declare memory for N blocks at run time, we will read N elements, will print them and also print the sum of all elements.

Consider the program:



#include<stdio.h>
#include<stdlib.h>

int main()
{
	int *ptr;	//declaration of integer pointer
	int limit;	//to store array limit
	int i;		//loop counter
	int sum;	//to store sum of all elements

	printf("Enter limit of the array: ");
	scanf("%d",&limit);

	//declare memory dynamically
	ptr=(int*)malloc(limit*sizeof(int));

	//read array elements
	for(i=0;i<limit;i++)
	{
		printf("Enter element %02d: ",i+1);
		scanf("%d",(ptr+i));
	}

	//print array elements
	printf("\nEntered array elements are:\n");
	for(i=0;i<limit;i++)
	{
		printf("%d\n",*(ptr+i));
	}
	
	//calculate sum of all elements
	sum=0;	//assign 0 to replace garbage value
	for(i=0;i<limit;i++)
	{
		sum+=*(ptr+i);
	}
	printf("Sum of array elements is: %d\n",sum);
	
	//free memory
	free(ptr);	//hey, don't forget to free dynamically allocated memory.
	
	return 0;
}

Output

Enter limit of the array: 5
Enter element 01: 100
Enter element 02: 200
Enter element 03: 300
Enter element 04: 400
Enter element 05: 500

Entered array elements are:
100
200
300
400
500
Sum of array elements is: 1500





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