# Algorithm for fractional knapsack problem

In this article, we are going to learn about **fractional knapsack problem**. **Algorithm for fractional knapsack with its example** is also prescribed in this article.

Submitted by Abhishek Kataria, on August 02, 2018

## Knapsack problem

The **knapsack problem or rucksack problem** is a problem in combinative or integrative optimization. In this kind of problem, there are set of items are given with a weight and a value, determine the number of each item included in a collection so that the total weight is less than or equal to the given limit and the total value is as large as possible.

## Fractional Knapsack problem

In **fractional knapsack fractions** of an item can be taken rather than having to make a binary choice for each of them. In this objective function is mathematically represented by:

Max

Where, **Pi= profit and Xi = fraction**.

Where, **Wi = weight** of the corresponding and **Xi= fraction**.

In this, at last, the output should be an array of the fraction item that we have taken, and in this, we also have to take output that gives the maximum profit.

### Algorithm for fractional knapsack

1. W and item have value V_{i}and weight W_{i}. 2. Rank item by value/weight ratio: V_{i}/W_{i}. 3. Thus : V_{i}/W_{i}= V_{j}/W_{j}for all i<=W_{j}. 4. Consider items in order of descending ratio. 5. Take as much of each item is possible. 6. Assume value and weight arrays are sorted by Vi<=Wi fractional knapsack (V,w,W) 7. Load:=0 8. i:=1 9. while load<w and i<=n loop 10. if 11. wi <=W –loop then 12. take all of item i 13. else 14. take (W-load)/wi of item i 15. end if 16. Add weight of what was taken to load. 17. i:i+1 18. end loop 19. return loop

**Example of fractional knapsack for the following instance by using greedy approach in which maximum value, M =25kg.**

S.no | Weight | Profit |
---|---|---|

1 | 10 | 30 |

2 | 5 | 20 |

3 | 15 | 40 |

4 | 8 | 36 |

**P=**

30 | 20 | 40 | 36 |

**W=**

10 | 5 | 15 | 8 |

**Now we will calculate the profit per unit capacity of knapsack: P/W**

3 | 4 | 2.6 | 4.5 |

**Now the fraction i.e. X**

1 | 1 | 2/15 | 1 |

**i.e. to calculate a total profit:**

P = P1X1 + P2X2 + P3X3 + P4X4 = 30×1+20×1+40×2/15+36×1 = 91.33

**Quick links:**

C FAQ(s)
C Advance programs
C/C++ Tips & Tricks
Puzzles
JavaScript
CSS
Python
Linux Commands
PHP
Android
Articles
More...

**Featured post:**

Introduction to Linux (Its modes, Safety, Most popular Applications)

Linux Best Distribution Software (Distros) of 2018

Was this page helpful? Please share with your friends...

Are you a blogger? Join our Blogging forum.

Comments and Discussions