Home » Python

Check whether the given string is a keyword or not using keyword module

Python keyword module example: Here, we are going to learn how to check whether the given string is a keyword or not using keyword module in Python?
Submitted by Bipin Kumar, on November 01, 2019

In this program, a string will be given by the user and we have to check whether it is a keyword in Python or not. To do this task in Python we will use a module which name is the keyword. Before going to do this task we will see a program that will return all keywords of Python programming language.

Python program to print all keyword

# importing the module
import keyword

# getting the list of all keywords
List_of_key=keyword.kwlist

# printing the number of keywords
print("No of keyword in Python: ",len(List_of_key))

#To print lists of all keyword present in Python.
print("List of keyword:",List_of_key)

Output

No of keyword in Python:  33
List of keyword: ['False', 'None', 'True', 'and', 'as', 'assert', 'break', 
'class', 'continue', 'def', 'del', 'elif', 'else','except', 'finally', 'for', 
'from', 'global', 'if', 'import', 'in', 'is', 'lambda', 'nonlocal', 'not', 'or', 
'pass', 'raise','return', 'try', 'while', 'with', 'yield']

Note:

  • Here, we have seen that the total keyword in Python language is 33.
  • Python does not allow us to use the keyword as a variable in the program.

Algorithm to check given string is a keyword or not?

  1. Initially, we will include the keyword module in Python by using the import function.
  2. Take the input string from the user.
  3. Take a list of all keyword in a variable by using kwlist() function from the module keyword.
  4. Check the given string is lies in the above-created list or not by using the keyword of Python.
    1. If it lies in the list then print the given string is a keyword in the Python programming language.
    2. If it does not lie in the list then print the given string is not a keyword in the Python programming language.

So, let's start writing the python program by the implementation of the above algorithm,

Python program to check whether given string is a keyword or not

# importing the module
import keyword

# input a string
str=input("Enter a string: ")

# getting a list of all keywords
List_of_key=keyword.kwlist

# checking whether given string is a keyword or not
if str in List_of_key:
    print("String {} is a keyword.".format(str))
else:
    print("String {} is not a keyword.".format(str))

Output

RUN 1:
Enter a string: includehelp
String includehelp is not a keyword.

RUN 2:
Enter a string: try
String try is a keyword.

RUN 3:
Enter a string: nonlocal
String nonlocal is a keyword.





Comments and Discussions

Ad: Are you a blogger? Join our Blogging forum.




Languages: » C » C++ » C++ STL » Java » Data Structure » C#.Net » Android » Kotlin » SQL
Web Technologies: » PHP » Python » JavaScript » CSS » Ajax » Node.js » Web programming/HTML
Solved programs: » C » C++ » DS » Java » C#
Aptitude que. & ans.: » C » C++ » Java » DBMS
Interview que. & ans.: » C » Embedded C » Java » SEO » HR
CS Subjects: » CS Basics » O.S. » Networks » DBMS » Embedded Systems » Cloud Computing
» Machine learning » CS Organizations » Linux » DOS
More: » Articles » Puzzles » News/Updates


© https://www.includehelp.com some rights reserved.