Home » Interview coding problems/challenges

# Where is my seat?

Here, we are going to learn about the **implementation of a coding problem where is my seat**? This is competitive coding type problem.

Submitted by Debasis Jana, on March 22, 2019

**Problem statement:**

You and your friend are deciding to go for a tour by train. But before booking the ticket of the train, your friend asks you to book a ticket in such a way that both of you sit face to face.

Seating decoration is known to you (given in the image) and you as a VIP customer are allowed to book seat number according to your choice.

After booking the ticket accordingly, your friend asks you, your seat number so that he can **check which is his seat number and seat position (WS/MS/AS)?**

**Example:**

Input: You have given your seat numberNOutput: Print your friend's seat number and seating position WS: For Window Seat MS: For Middle Seat AS: For Aisle Seat ----------------- Sample Input: 57 23 Sample Output: 52 AS 14 MS

**Note:** Before going to solution, we recommend you to try it by yourself first...

**Hint:** Starting from bottom to top (1 to 6) sees the difference of opposite seat number, **[11,9,7,5,3,1]**

**Algorithm:**

1. Take input N 2. Switch (N%12) 2.1 Case 1: print N+11 and "WS" 2.2 Case 2: print N+9 and "MS" 2.3 Case 3: print N+7 and "AS" 2.4 Case 4: print N+5 and "AS" 2.5 Case 5: print N+3 and "MS" 2.6 Case 6: print N+1 and "WS" 2.7 Case 7: print N-1 and "WS" 2.8 Case 8: print N-3 and "MS" 2.9 Case 9: print N-5 and "AS" 2.10 Case 10: print N-7 and "AS" 2.11 Case 11: print N-9 and "MS" 2.12 Default : print N-11 and "WS" 3. END OF PROGRAM

**Explanation:**

Here we are finding mod of **N** (entered seat number) by 12 because there are 12 seats in a single cabin of the train. Now, if we divide it by 12 we will be able to identify each seat individually by its number, first 6 (1 to 6) are at the left side and next 6 (7 to 12) are at the right side.

For example, if **N=52** then, **N%12=4**, so **52 ^{nd}** seat will get a unique number in that particular cabin and it is at the left side.

Now, by seeing the given picture we can say that difference between seat number 1 and 12 is 11, 2 and 11 is 9 and so on, means its decreasing by two, starting from 11.

So, for seat number 4 difference will be 5, that's why the opposite seat of 52 is 52+5=57.

Similarly, for **N=23,** the mod value is 11, and the seat difference of the opposite seat will be 9. But in this case, we have to deduct 9 from **N** because **N** is at the right side. So, ans: is **23-9=14**.

**C++ implementation:**

#include <bits/stdc++.h> using namespace std; int main(){ int N; //taking your seat number cin>>N; switch(N%12) { // Finding modulous of 12 because there are 12 seats in a cabin // First 6 seats are at left side and next 6 seats (7 to 12) //are at right side of a cabin case 1: cout<<N+11<<" WS"; break; //if modulous is 2 then we can see that seat number is 2 case 2: //so here the opposite seat is at right side and //seat difference is 9 cout<<N+9<<" MS"; break; case 3: // here seat difference is 7 and opposite //side is at right side cout<<N+7<<" AS"; break; case 4: cout<<N+5<<" AS"; break; case 5: cout<<N+3<<" MS"; break; case 6: cout<<N+1<<" WS"; break; // as said above seat number from 7 to 12 are at right side // so opposite seat will be at left side and seat difference is 1 case 7: cout<<N-1<<" WS"; break; case 8: cout<<N-3<<" MS"; break; case 9: cout<<N-5<<" AS"; break; case 10: cout<<N-7<<" AS"; break; case 11: cout<<N-9<<" MS"; break; default: cout<<N-11<<" WS"; break; } return 0; }

**Output**

TOP Interview Coding Problems/Challenges

- Run-length encoding (find/print frequency of letters in a string)
- Sort an array of 0's, 1's and 2's in linear time complexity
- Checking Anagrams (check whether two string is anagrams or not)
- Relative sorting algorithm
- Finding subarray with given sum
- Find the level in a binary tree with given sum K
- Check whether a Binary Tree is BST (Binary Search Tree) or not
- 1[0]1 Pattern Count
- Capitalize first and last letter of each word in a line
- Print vertical sum of a binary tree
- Print Boundary Sum of a Binary Tree
- Reverse a single linked list
- Greedy Strategy to solve major algorithm problems
- Job sequencing problem
- Root to leaf Path Sum
- Exit Point in a Matrix
- Find length of loop in a linked list
- Toppers of Class
- Print All Nodes that don't have Sibling
- Transform to Sum Tree
- Shortest Source to Destination Path

Comments and Discussions

**Ad:**
Are you a blogger? Join our Blogging forum.

Learn PCB Designing: PCB DESIGNING TUTORIAL