# Binary Coded Decimal (BCD Code) and its addition

Here, we are going to learn about the **Binary Coded Decimal (BCD Code)** and its addition (**Binary Coded Decimal Addition**).

Submitted by Saurabh Gupta, on November 02, 2019

**Prerequisite:** Number systems

**BCD Code (8421 Code)**: In **BCD 8421 code**, each decimal digit is represented using a 4-bit binary number. The 4-bit binary numbers have their weights attached as 8, 4, 2, 1 from MSB to LSB side. Since the weights are attached to it comes in the category of **weighted codes** and is also **sequential**.

In a digital system that accepts only binary numbers in form of 0 and 1, the only way to interpret decimal numbers is its conversion from decimal to binary and vice-versa which is a slow process and it also requires a huge electronic circuitry. So, we use BCD numbers. Also, the sequential nature of BCD numbers makes it advantageous for performing arithmetic operations.

Although, there are many advantages there are some disadvantages too such as:

BCD codes are more inefficient than usual binary codes. Usually, in binary numbers, we represent **(13) _{10} = (1101)_{2}** i.e., we require 4-bits but in BCD notation

**(13)**is represented as

_{10}**(0001 0011)**. Here, we require 8-bits to represent the same

**13**.

Another disadvantage is that arithmetic operations become more complex as compared to the usual binary numbers because, in BCD numbers, we have **6 illegal** states as **1010, 1011, 1100, 1101, 1110 and 1111** which are not part of **8421 BCD system**.

The following table describes the relation between Decimal, Binary and **8421 BCD numbers**.

Decimal Numbers | Binary Numbers | 8421 BCD Numbers |
---|---|---|

0 | 0000 | 0000 |

1 | 0001 | 0001 |

2 | 0010 | 0010 |

3 | 0011 | 0011 |

4 | 0100 | 0100 |

5 | 0101 | 0101 |

6 | 0110 | 0110 |

7 | 0111 | 0111 |

8 | 1000 | 1000 |

9 | 1001 | 1001 |

10 | 1010 | 0001 0000 |

11 | 1011 | 0001 0001 |

12 | 1100 | 0001 0010 |

13 | 1101 | 0001 0011 |

14 | 1110 | 0001 0100 |

15 | 1111 | 0001 0101 |

... | ... | ... |

... | ... | ... |

... | ... | ... |

**Example 1: Represent (28) _{10} and (53)_{10} in 8421 BCD notation**

**Solution:**

**(28) _{10}** in BCD notation can be represented as

**(0010 1000)**.

Similarly, **(53) _{10}** in BCD notation can be represented as

**(0101 0011)**.

### BCD Addition

The **addition of BCD numbers** is slightly different from **binary addition**. Here, the rules of binary addition are partially applicable only to the individual 4-bit groups. The **BCD addition**, is thus carried out by individually adding the corresponding 4-bit groups starting from the LSB side and if there is a carry to the next group, or if the result belongs to any of the 6 illegal states than we add **6 _{10}(0110)** to the sum term of that group and resulting carry is added in the next group.

**Example: Perform BCD Addition of 6 and 7.**

**Solution:** BCD representation of **6** is given as **0110** and for **7** it is **0111**.

When we add **6** and **7** in **BCD**, we get **1101** which is an invalid state therefore, we add **0110 (6)** to the sum to get correct result which is **0001 0011 (13)**.

**Example 2: Perform BCD Addition of 8765 and 3943.**

**Solution:**

BCD representation of **8765** is given as **1000 0111 0110 0011** and for **3943** it is **0011 1001 0100 0011**.

Firstly, we will perform a normal **binary addition** of two numbers now we see **1100** and **1010** which are illegal states also the third group of 4-bits from LSB side i.e., **0000** has a carry **1** to the next group. So, for correction, we have to add **0110** to all three groups. Thus, we get the correct result as **0001 0010 0111 0000 1000** which is equivalent to **(12708) _{10}** in decimal number system and this is what we get on adding

**(8765)**. Hence, our result is also verified.

_{10}+ (3943)_{10}= (12708)_{10}TOP Interview Coding Problems/Challenges

- Run-length encoding (find/print frequency of letters in a string)
- Sort an array of 0's, 1's and 2's in linear time complexity
- Checking Anagrams (check whether two string is anagrams or not)
- Relative sorting algorithm
- Finding subarray with given sum
- Find the level in a binary tree with given sum K
- Check whether a Binary Tree is BST (Binary Search Tree) or not
- 1[0]1 Pattern Count
- Capitalize first and last letter of each word in a line
- Print vertical sum of a binary tree
- Print Boundary Sum of a Binary Tree
- Reverse a single linked list
- Greedy Strategy to solve major algorithm problems
- Job sequencing problem
- Root to leaf Path Sum
- Exit Point in a Matrix
- Find length of loop in a linked list
- Toppers of Class
- Print All Nodes that don't have Sibling
- Transform to Sum Tree
- Shortest Source to Destination Path

Comments and Discussions

**Ad:**
Are you a blogger? Join our Blogging forum.