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A fully submerged orifice with a diameter of 0.5 meters is subjected to a head of 2 meters. Calculate the approximate discharge through the orifice. Use a discharge coefficient of 0.61
13. A fully submerged orifice with a diameter of 0.5 meters is subjected to a head of 2 meters. Calculate the approximate discharge through the orifice. Use a discharge coefficient of 0.61.
- 0.152 m³/s
- 0.248 m³/s
- 0.412 m³/s
- 0.685 m³/s
Answer: B) 0.248 m³/s
Explanation:
The discharge through a fully submerged orifice can be calculated using the formula:
Q = Cd * A * √ (2 * g * h)
Where:
Q = Discharge
Cd = Discharge coefficient (0.61)
A = Area of the orifice (π * r²)
r = Radius of the orifice (d/2)
g = Acceleration due to gravity (9.81 m/s²)
h = Head over the orifice (2 meters)
Putting the values:
r = 0.1 / 2 = 0.05 m
A = π * (0.05 m) ² ≈ 0.007853 m²
Q = 0.61 * 0.007853 m² * √ (2 * 9.81 m/s² * 2 m) ≈ 0.248 m³/s